A Costume That’s Off the Depp End!

Halloween is this Saturday, and one of the best things about the holiday is how creative people get with their costumes.

This creativity can come in several forms. Sometimes, it’s the costume itself, an idea that wows you as ambitious or clever or totally unexpected. Other times, it’s the execution of the costume, either in how impressive the effort involved is OR how ingeniously they’ve kept their budget reasonable.

In college one year, I was short on funds for a costume. But one thing never in short supply around Halloween are empty candy wrappers. So I took an old shirt, glued candy wrappers to it (along with some stray kernels of popcorn and an old cell phone) and I went to a costume party as the floor of a movie theater.

It’s one of my favorite costumes to this day, because it required me to think outside the box.

Today’s post is also about a costume that’s outside the box. Many people dress up as celebrities or famous fictional characters for Halloween, but rarely do they dress up as many characters simultaneously.

Check out the photo below! Our costumed gentleman has decked himself out in the trappings of numerous Johnny Depp films. Can you name them all?

This is a great costume, not only because it’s ambitious and meticulously put together, but because there’s clearly a great deal of thought behind it. Terrific stuff!

Oh, and if you’re looking for more puzzly costume fun, check out our Follow-Up Friday post this week, as we celebrate our Third Annual PuzzleNation Punderful Costume Game!


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A PuzzleNation First Look: Will Sudoku

Sudoku puzzles haven’t been around all that long, especially when compared to the hundred-plus years of longevity that the crossword puzzle brings to the table. Nonetheless, Sudoku puzzles remain one of the most popular puzzles these days, whether solved with pen and paper or in app form.

I’ve written about some of the many Sudoku variants before, but today’s post is something different. It’s the debut of a brand-new type of Sudoku. That’s right! I have the distinct pleasure of introducing you to Will Sudoku, the creation of topnotch puzzler Bassey Godwin.

This is a standard Will Sudoku grid. (Not to be confused with the Will Shortz’s Sudoku magazine.)

Named in honor of puzzle master and New York Times Crossword editor Will Shortz, Will Sudoku offers a challenge that your average Sudoku puzzle cannot match.

Instead of placing the numbers 1-9 in a 9×9 grid so that each row, column, and 3×3 box features all nine numbers without repeats, Will Sudoku tasks you with filling in the grid in such a way that the numbers 1-8 appear only once in each of the rows and columns as well as the 4×4 boxes.

As you can see, each row and column is split into two tracks, inside and outside. Horizontal lines are indicated by the similar triangular cells in the corresponding boxes in a row. For instance, horizontal line 1 contains 45238761; horizontal line 2 contains 23816457, as shown above.

The vertical lines work the same way, with outside and inside tracks within each column. This tight arrangement means a LOT of information is available to a keen-eyed solver, but there are also more spots to place your numbers.

There are numerous variations included in this puzzle bundle:

  • Will Triangular Box Sudoku: Instead of 4×4 squares, the grid is divided into large triangles that contain all 8 numbers
  • Will Horizontal Bar Sudoku and Will Vertical Bar Sudoku: Instead of the 4×4 squares, the grid is divided into vertical or horizontal bars that contain all 8 numbers
  • Will Variable Boxes Sudoku: A mix of 4×4 squares, vertical and horizontal bars, and triangles appear in a single grid

In addition to these variations, Bassey experiments with the form and offers a few new twists on his established template.

  • Will Sudoku Word Search: Instead of the numbers 1-8, eight letters appear in a grid, and once you’ve finished placing them all, you search the grid Word Seek-style to find an 8-letter word reading out in some direction
  • Will Trigonal Sudoku: A Will Sudoku grid is divided diagonally, leaving you half a grid to solve. Cleverly enough, each of the three sides of the triangle also adhere to standard Will Sudoku rules, with all 8 digits appearing once each.
  • Finally, and most challengingly, there is Will Samurai Sudoku, where you confront five interconnected Will Sudoku grids in one monster puzzle.

This debut collection of Will Sudoku offers 150 puzzles for $10!

As a solver, I was very impressed with how many different solving styles emerged from the Will Sudoku template. And going from nine numbers to eight certainly didn’t decrease the puzzle’s difficulty! (The new inside and outside tracks in each column and row certainly took a little getting used to.)

The puzzles marked “average” will keep you on your toes, and some of the ones marked “tough” will really test your deduction and logic skills. But for the price, you simply can’t go wrong.

Thank you to Bassey Godwin for giving PuzzleNation Blog the exclusive first look at Will Sudoku and allowing us to share this clever new Sudoku variant with our fellow PuzzleNationers and the online puzzle community at large!

But before I go, I want to leave you with one last surprise: a video of Bassey himself solving a Sudoku puzzle blindfolded! It’s mind-blowing stuff, and the perfect sendoff for this post. Take it away, Bassey!


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A pickle of a puzzler!

A little touch of absurdity never hurts when it comes to a good logic problem or brain teaser.

There’s the classic river-crossing puzzle (with either a fox, a goose, and a bag of beans and or a wolf, a goat, and a cabbage) that challenges you to get all three across without one eating one of the others, but it never explains why you have a wolf or a fox in the first place!

We never really question why we need to know the weights of castaways or why knowing the color of your hat might save your life; we just accept the parameters and forge onward.

Some brain teasers, curiously enough, seem intentionally nonsensical by design. Many claim that Lewis Carroll’s famous Alice in Wonderland riddle “Why is a raven like a writing-desk?” was created without a solution. Of course, that hasn’t stopped many (myself included) from posing solutions to the riddle anyway.

And that brings us to today’s brain teaser — “Pickled Walnuts” by Hubert Phillips — which I discovered on io9.com:

You are given a series of statements which may seem to you more or less absurd. But, on the assumption that these statements are factually correct, what conclusion (if any) can be drawn?

1. Pickled walnuts are always provided at Professor Piltdown’s parties.
2. No animal that does not prefer Beethoven to Mozart ever takes a taxi in Bond Street
3. All armadillos can speak the Basque dialect.
4. No animal can be registered as a philatelist who does not carry a collapsible umbrella.
5. Any animal that can speak Basque is eligible for the Tintinnabulum Club.
6. Only animals that are registered philatelists are invited to Professor Piltdown’s parties.
7. All animals eligible for the Tintinnabulum Club prefer Mozart to Beethoven.
8. The only animals that enjoy pickled walnuts are those who get them at Professor Piltdown’s.
9. Only animals that take taxis in Bond Street carry collapsible umbrellas.

I will tell you, as a starter, that a conclusion CAN definitively be drawn from these statements. (Honestly, if there wasn’t some solution, I wouldn’t waste your time with it.)

So, what conclusion can be drawn from these statements?

Armadillos do not enjoy pickled walnuts!

How do I know this for sure? Allow me to walk you through my deductive process.

We know that all armadillos speak Basque, according to statement 3. Therefore, according to statement 5, armadillos are eligible for the Tintinnabulum Club.

Now, according to statement 7, armadillos prefer Mozart to Beethoven. But, in statement 2, we’re told that no animal that does not prefer Beethoven to Mozart ever takes a taxi in Bond Street, which means that armadillos do NOT take taxis in Bond Street.

Therefore, according to statement 9, armadillos do not carry collapsible umbrellas, which also disqualifies them from being registered as philatelists, according to statement 4. And since only registered philatelists are invited to Professor Piltdown’s parties (according to statement 6), armadillos are not invited to the Professor’s parties.

Finally, statement 8 tells us that the only animals that enjoy pickled walnuts are those who get them at Professor Piltdown’s, which means armadillos do not enjoy pickled walnuts!

Honestly, I didn’t find this brain teaser particularly difficult because you can find those middle links very quickly, and by linking more and more statements, you eventually find the two ends — armadillos and pickled walnuts — and your conclusion is waiting for you.

This would’ve been a more difficult puzzle if some red-herring statements were thrown in that didn’t connect to the rest, like “All squirrels on Beaumont Avenue have Tuesdays off” or “The birdbaths on Bond Street were designed by a German sculptor who enjoyed hot dogs.”

Nonetheless, this is a terrific exercise in finding order in what at first appears to be chaos. It’s what puzzlers do: we make sense of the universe, one puzzle at a time.


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View a Clue: Common Crossword Words!

Welcome to a brand-new feature on PuzzleNation Blog: the View a Clue game!

I talk about crosswords a lot here, and rightfully so. Crosswords are the most famous pen-and-paper puzzles in the world, and here at PuzzleNation, you can always find terrific, fresh puzzle content for our Penny Dell Crosswords App!

And although I love running our daily Crossword Clue Challenge on Facebook and Twitter, I wanted to try something different today.

I’ve selected ten words that commonly show up in crossword grids — some crosswordese, some not — and I want to see if the PuzzleNation readership can identify them from pictures. It’s a visual puzzle I call View a Clue!

Let’s give it a shot!


#1 (4 letters)

#2 (4 letters)

#3 (4 letters)

#4 (4 letters)

#5 (4 letters)

#6 (4 letters)

#7 (3 letters)

#8 (4 letters)

#9 (4 letters)

#10 (4 letters)


How many did you get? Let me know in the comments below! And if you’d like to see another View a Clue game (maybe about common names in crosswords or crosswordy animals!), tell us below!

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Goodbye, Merl.

[Picture courtesy of crosswordfiend.com.]

The puzzle world was stunned this weekend by the sudden passing of a true crossword legend: Merl Reagle.

Merl has been one of the biggest names in puzzles for a long time now, one of the few crossword constructors who was successful and prolific enough to work on puzzles full-time.

Between his appearance in the Wordplay documentary and a cameo on The Simpsons alongside New York Times crossword editor Will Shortz, he proudly represented both the love of puzzles so many solvers share AND stood as a standard-bearer for crossword construction and quality puzzling.

Merl sold his first crossword to the New York Times at age 16 — ten years after he started constructing puzzles, amazingly enough! In a career spanning five decades, his contributions to the world of puzzles were myriad. Nearly every year, one of his puzzles appears at the American Crossword Puzzle Tournament. The crossword he constructed for the 100th Anniversary of the Crossword was turned into a Google Doodle, and, based on my research, is the most solved crossword puzzle in history.

A craftsman with humor and heart (and no small amount of anagram skill), Merl was truly one of a kind.

[Picture courtesy of tucson.com.]

I had the privilege of meeting him at the American Crossword Puzzle Tournament this year. It was only for a few minutes while the tournament participants were tackling one of the early puzzles and the vendor’s floor was pretty empty. (Otherwise, there were always puzzlers crowded around Merl’s table between tournament puzzles. He was the center of gravity around which many fellow puzzle fans orbited, a master of ceremonies wherever he went.)

He was friendly and gracious, one of those people who can strike an instant rapport with virtually anyone. He put me at ease immediately as I checked out his latest puzzly offerings and we briefly chatted about the tournament itself. (I didn’t get the chance to challenge his legendary anagramming talents, sadly.)

Fellow puzzler and friend of the blog Keith Yarbrough was kind enough to share one of this experiences with Merl:

Merl gave me his philosophy of puzzle construction at the ACPT one year. His goal, he said, was to make the solver smile. Coming up with a funny theme was the main thing. His test when he came up with an idea was to run it past his wife, who is not a puzzler. If it made her smile, it was a keeper.

He wasn’t out to frustrate the solver with obscurities or unnecessary crosswordese, so he used common entries as much as possible. His mantra was that the fill should not be overly difficult.

[Picture courtesy of cltampa.com.]

The dozens of tributes I’ve seen online are a testament to how many friends and admirers Merl earned over the years. There are too many to link to here, but I want to highlight a few from fellow puzzlers Brendan Emmett Quigley, Deb Amlen, and David Steinberg.

Merl, you will be missed. Thank you, for the laughs, for the tough crossings, the trickiest-of-tricky clues, and the many unexpected delights you managed to spring on so many solvers.

You can check out Merl’s work on his Sunday Crosswords website as well as some of his collections on Amazon. Click the links. You won’t regret it.

Thanks for visiting PuzzleNation Blog today! You can share your pictures with us on Instagram, friend us on Facebook, check us out on TwitterPinterest, and Tumblr, and be sure to check out the growing library of PuzzleNation apps and games!

A ten-digit brain teaser to melt your mind!

I’ve started to develop a reputation as something of a brain-teaser pro, given some of the beastly brain teasers we’ve featured on the blog over the last few months.

And, as such, I’ve started to receive brain teasers from friends and fellow puzzlers, challenging me to unravel them AND explain my methods to the PuzzleNation audience.

I’ve never been one to shirk a challenge, so here we go! This puzzle is entitled Mystery Number, and a little googling after solving it reveals it most likely came from this Business Insider link. (Although their solution is slightly flawed.)

Enjoy!


There is a ten-digit mystery number (not starting with zero) represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?

1. A + B + C + D + E = a multiple of 6.
2. F + G + H + I + J = a multiple of 5.
3. A + C + E + G + I = a multiple of 9.
4. B + D + F + H + J = a multiple of 2.
5. AB = a multiple of 3.
6. CD = a multiple of 4.
7. EF = a multiple of 7.
8. GH = a multiple of 8.
9. IJ = a multiple of 10.
10. FE, HC, and JA are all prime numbers.

(And to clarify here for clues 5 through 9, AB is a two-digit number reading out, NOT A times B.)


[Image courtesy of Wikipedia.]

Now, anyone who has solved Kakuro or Cross Sums puzzles will have a leg up on other solvers, because they’re accustomed to dealing with multiple digits adding up to certain sums without repeating numbers. If they see three boxes (which would essentially be A + B + C) and a total of 24, they know that A, B, and C will be 7, 8, and 9 in some order.

[For those unfamiliar with Cross Sums or Kakuro solving, feel free to refer to this solving aid from our friends at Penny/Dell Puzzles, which includes a terrific listing of possible number-combinations that will definitely prove useful with this brain teaser.]

And since the digits 0 through 9 add up to 45, that provides a valuable starting hint for clues 1 and 2 (in which all 10 digits appear exactly once). A multiple of 6 (6, 12, 18, 24, 30, 36, 42) plus a multiple of 5 (5, 10, 15, 20, 25, 30, 35, 40, 45) will equal 45. And there’s only one combination that works.

So A + B + C + D + E must equal 30, and F + G + H + I + J must equal 15.

The same logic applies to clues 3 and 4 (in which all 10 digits appear exactly once). A multiple of 9 (9, 18, 27, 36, 45) plus a multiple of 2 (2, 4, 6, 8, 10, etc.) will equal 45. And there’s only one combination that works.

So A + C + E + G + I must equal 27, and B + D + F + H + J must equal 18.

And now, we jump to clue 9. Since IJ is a multiple of 10, and all multiples of 10 end in 0, we know J = 0.

This tells us something about JA in clue 10. J is 0, which means A can only be 2, 3, 5, or 7.

There may a quicker, more deductive manner of solving this puzzle, but I couldn’t come up with it. I went for a brute force, attrition-style solve.

So I wrote out all of the possibilities for clues 5 through 9, and began crossing them off according to what I already knew. Here’s what we start with:

AB = 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99
CD = 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96
EF = 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98
GH = 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96
IJ = 10, 20, 30, 40, 50, 60, 70, 80, 90

Now, we can remove any double numbers like 33 because we know each letter represents a different number.

AB = 12, 15, 18, 21, 24, 27, 30, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96
CD = 12, 16, 20, 24, 28, 32, 36, 40, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 92, 96
EF = 14, 21, 28, 35, 42, 49, 56, 63, 70, 84, 91, 98
GH = 16, 24, 32, 40, 48, 56, 64, 72, 80, 96
IJ = 10, 20, 30, 40, 50, 60, 70, 80, 90

[Sorry guys, you’re out.]

And we know that J = 0, so we can remove any numbers that end in zero for AB, CD, EF, and GH.

AB = 12, 15, 18, 21, 24, 27, 36, 39, 42, 45, 48, 51, 54, 57, 63, 69, 72, 75, 78, 81, 84, 87, 93, 96
CD = 12, 16, 24, 28, 32, 36, 48, 52, 56, 64, 68, 72, 76, 84, 92, 96
EF = 14, 21, 28, 35, 42, 49, 56, 63, 84, 91, 98
GH = 16, 24, 32, 48, 56, 64, 72, 96
IJ = 10, 20, 30, 40, 50, 60, 70, 80, 90

And for AB, we know that A can only be 2, 3, 5, or 7, so we can delete any numbers that don’t start with one of those four digits.

AB = 21, 24, 27, 36, 39, 51, 54, 57, 72, 75, 78
CD = 12, 16, 24, 28, 32, 36, 48, 52, 56, 64, 68, 72, 76, 84, 92, 96
EF = 14, 21, 28, 35, 42, 49, 56, 63, 84, 91, 98
GH = 16, 24, 32, 48, 56, 64, 72, 96
IJ = 10, 20, 30, 40, 50, 60, 70, 80, 90

Hmmm, that’s still a LOT of options. What else do we know?

Well, we know from clue 10 that FE and HC are prime numbers. So they can’t be even numbers OR end in a 5. So we can eliminate any options from CD and EF that begin with an even number or a 5.

AB = 21, 24, 27, 36, 39, 51, 54, 57, 72, 75, 78
CD = 12, 16, 32, 36, 72, 76, 92, 96
EF = 14, 35, 91, 98
GH = 16, 24, 32, 48, 56, 64, 72, 96
IJ = 10, 20, 30, 40, 50, 60, 70, 80, 90

Alright, now we need to look at those big addition formulas again. Specifically, we need to look at B + D + F + H + J = 18.

We know J = 0, so the formula becomes B + D + F + H = 18. Now, take a look at our lists of multiples for AB, CD, EF, and GH. Look at the second digit for each. There’s a little nugget of information hiding inside there.

Every D and H digit is an even number. Which means that B and F must either both also be even, or both be odd in order to make an even number and add up to 18.

But, wait, if they were both even, then they would use all of our even numbers, and some combination of B, D, F and H would be 2 + 4 + 6 + 8, which equals 20. That can’t be right!

So let’s delete any even numbered options from AB and EF.

AB = 21, 27, 39, 51, 57, 75
CD = 12, 16, 32, 36, 72, 76, 92, 96
EF = 35, 91
GH = 16, 24, 32, 48, 56, 64, 72, 96
IJ = 10, 20, 30, 40, 50, 60, 70, 80, 90

Okay, we’ve whittled down EF to 2 possibilities: 35 and 91. [Here is where the Business Insider solution goes awry, because they never eliminate one of these two options.]

Clue 10 tells us that FE is a prime number, but that doesn’t help, because both 53 and 19 are prime. So now what?

Let’s return to those starting formulas.

We know that A + B + C + D + E = 30, and our handy-dandy number-combination listing tells us there are six possible ways that five digits can add up to 30: 1-5-7-8-9; 2-4-7-8-9; 2-5-6-8-9; 3-4-6-8-9; 3-5-6-7-9; and 4-5-6-7-8.

Look at the possibilities for A, B, C, D, and E according to our work thus far:

AB = 21, 27, 39, 51, 57, 75
CD = 12, 16, 32, 36, 72, 76, 92, 96
EF = 35, 91

There’s not a single 8 in any of those pairings! And five of our six possible answers for A + B + C + D + E = 30 include an 8 as one of the five digits.

Therefore, 3-5-6-7-9 and A-B-C-D-E match up in some order.

EF is either 35 or 91, but with both 3 and 5 counted among the letters in A-B-C-D-E, EF cannot be 35, so EF is 91. Let’s eliminate any option for AB, CD, GH, or IJ that include 9 or 1.

AB = 27, 57, 75
CD = 32, 36, 72, 76
EF = 91
GH = 24, 32, 48, 56, 64, 72
IJ = 20, 30, 40, 50, 60, 70, 80

Because E = 9, that leaves 3, 5, 6, and 7 as the only possible digits available for A, B, C, and D. So let’s eliminate any combinations that use numbers other than those four.

AB = 57, 75
CD = 36, 76
EF = 91
GH = 24, 32, 48, 56, 64, 72
IJ = 20, 30, 40, 50, 60, 70, 80

We can also eliminate any combinations for GH and IJ that include those four numbers.

AB = 57, 75
CD = 36, 76
EF = 91
GH = 24, 48
IJ = 20, 40, 80

Since our only possibilities for AB use 5 and 7 in some order, CD cannot be 76, so it must be 36.

AB = 57, 75
CD = 36
EF = 91
GH = 24, 48
IJ = 20, 40, 80

So, here are our options at this point:

AB = 57, 75
CD = 36
EF = 91
GH = 24, 48
IJ = 20, 40, 80

All possible solutions for GH include the number 4, so we can delete 40 as a possibility for IJ.

AB = 57, 75
CD = 36
EF = 91
GH = 24, 48
IJ = 20, 80

Let’s look at those formulas one more time. We know A + C + E + G + I = 27.

We also know C = 3 and E = 9, so A + G + I = 15. And the only combination of available digits that allows for that is 5, 2, and 8, meaning AB = 57, GH = 24, and IJ = 80.

So ABCDEFGHIJ = 5736912480.


I don’t think I’ve tackled a puzzle this tough since the seesaw brain teaser!

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