It’s Follow-Up Friday: Sharknado puzzle edition!

Welcome to Follow-Up Friday!

By this time, you know the drill. Follow-Up Friday is a chance for us to revisit the subjects of previous posts and bring the PuzzleNation audience up to speed on all things puzzly.

And today, we’re returning to the subject of holidays.

I like to talk about puzzly holidays, but this week has marked more of a cinematic holiday.

Yes, for the third summer in a row, a Sharknado movie has rampaged across our screens, bringing ridiculous action and inexplicable acts of shark-fighting heroism to millions of viewers.

And I thought to myself, what better way is there to mark the occasion than to create a Sharknado-themed deduction puzzle?

So that’s exactly what I did! Enjoy!

Sharknados are terrorizing cities across America! Every day, one of our heroes (April, Claudia, Fin, Gilbert, or Nova) has bravely ventured into a sharknado-afflicted city, armed with a weapon (baseball bat, chainsaw, grenade, laser, or rifle.)

No two heroes were in the same city on the same day, and no hero used any weapon more than once. No weapon was used more than once in the same day, nor was any weapon used more than once in the same city. Can you complete the schedule chart below?

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It’s Follow-Up Friday: For the Wynne edition!

Welcome to Follow-Up Friday!

By this time, you know the drill. Follow-Up Friday is a chance for us to revisit the subjects of previous posts and bring the PuzzleNation audience up to speed on all things puzzly.

And today, I’d like to return to the subject of Arthur Wynne.

[Image courtesy of express.co.uk.]

In 1913, Arthur Wynne created the first modern crossword puzzle — which he called a Word-Cross puzzle — and over a hundred years later, we are still enjoying the ever-increasing variety of puzzles and clues spawned by that “fun”-filled grid. (Click here for more details on that groundbreaking puzzle.)

Wynne was born on June 22, 1871 in Liverpool, England, but moved to the states in the early 1890s, spending time in Pittsburgh and New York City before creating his Word-Cross puzzle for the New York World. (We can also credit Wynne with the use of symmetrical black squares in crossword grids.)

So, in honor of Mr. Wynne’s 144th birthday, I’ve got a little word creation puzzle for you! How many words of four or more letters can you make from the letters in ARTHUR WYNNE’s name?

I came up with 110! Can you match or top my wordcount? Let me know!

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Letter rip! It’s lipogram time!

[Building words and phrases, one letter at a time.]

This week I did something a little different in the preview for today’s blog. Usually on Mondays, I post a brief preview of the week’s blog posts, Facebook and Twitter content, et cetera.

But instead of a short teaser about the entry, I posted the following clue:

How quickly can you find out what is unusual about this paragraph? It looks so ordinary that you would think that nothing was wrong with it at all and, in fact, nothing is. But it is unusual. Why? If you study it and think about it you may find out, but I am not going to assist you in any way. You must do it without coaching. No doubt, if you work at it for long, it will dawn on you. Who knows? Go to work and try your skill. Par is about half an hour.

Did you figure out what’s curious about it? It’s missing the letter E!

[A keyboard displaying the most commonly used letters in the language in delightful bar-graph form. It should come as no surprise which letter appears most frequently.]

That paragraph is a terrific example of a lipogram, a written work that purposely avoids or leaves out a given letter. Lipograms are part writing challenge and part puzzle, taxing your vocabulary and your creativity.

(Removing any letter can make things tougher. I remember when my friend’s L key on his keyboard stopped working. “I think it will do well” became “I think it wi do we” until he started using the 1 key as a substitute L.)

And if you think writing a paragraph without the letter E is tough, imagine writing an entire novel without it. Ernest Vincent Wright did just that in 1939 with his 50,000 word novel Gadsby. He even went so far as to rephrase famous lines by William Congreve and John Keats in order to keep the letter E away.

Gadsby partially inspired a French author named Georges Perec to do the same, and his novel La Disparition (also known as A Void) doesn’t feature a single E over the course of three hundred pages.

There are numerous other lipogrammatic works and puzzles, but I think my favorite is the novel Ella Minnow Pea by author Mark Dunn.

Not only is the novel told through letters or notes shared by several characters, but the narrative grows increasingly lipogrammatic as the story progresses.

Check out this summary from Wikipedia:

The novel is set on the fictitious island of Nollop, off the coast of South Carolina, which is home to Nevin Nollop, the supposed creator of the well-known pangram “The quick brown fox jumps over the lazy dog.” This sentence is preserved on a memorial statue to its creator on the island and is taken very seriously by the government of the island.

Throughout the book, tiles containing the letters fall from the inscription beneath the statue, and as each one does, the island’s government bans the contained letter’s use from written or spoken communication. A penalty system is enforced for using the forbidden characters, with public censure for a first offense, lashing or stocks (violator’s choice) upon a second offense and banishment from the island nation upon the third.

So as the book progresses, fewer and fewer letters are used! It’s both an impressive linguistic feat and a wonderful work of totalitarian satire. (And how can you not love a character’s name sounding like LMNOP?)

[In a Christmas episode of the ’90s cartoon Animaniacs, Wakko keeps spelling Santa “Santla,” inspiring a rousing, punny version of “Noel” to correct Wakko’s spelling.]

Our friends at Penny/Dell Puzzles have a lipogram puzzle: Dittos. In Dittos, you’re given a series of letters, and then told to spell five common words using those letters AND a given letter. You can repeat the given letter as many times as necessary.

For example, if you were given the letters AAENRY and then told to make 2 five-letter words, using D as many times as necessary, you might come up with DREAD and DANDY.

But what about the flip side? What if you decided you were only going to use one vowel? Well then, my ambitious friend, you’ve accepted the challenge of creating a univocalic.

I’m not familiar with any longer works that are univocalic. You usually see them in paragraph form or, occasionally, palindrome form. “A man, a plan, a canal… Panama!” is probably the most famous univocalic in history.

(Univocalics are not to be confused with supervocalics, which are words that include all five vowels, like sequoia or abstemious.)

I hope you’ve enjoyed this look at a curious subset of puzzles and wordplay. One of my fellow puzzlers suggested I pursue lipograms as a follow-up to my post a little while back about single-letter puzzles, and I couldn’t resist.

Have you ever tried to write a lipogram or univocalic, PuzzleNationers? Let me know! I’d love to see them!

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It’s Follow-Up Friday: Mother’s Day Answers edition!

Welcome to Follow-Up Friday!

By this time, you know the drill. Follow-Up Friday is a chance for us to revisit the subjects of previous posts and bring the PuzzleNation audience up to speed on all things puzzly.

And today, I’ll be posting the answers to our Mother’s Day Unscramblers puzzle!

On Sunday, in honor of the many puzzle-loving moms in the audience, I created a twofold challenge. First, you had to unscramble the names of 12 famous sitcom mothers, and then you had to match them with their respective TV shows.

So, without further ado and hullabaloo, here are the answers!

1. Marion Cunningham — H. Happy Days
2. Samantha Stephens — D. Bewitched
3. Morticia Addams — B. The Addams Family
4. Jill Taylor — L. Home Improvement
5. Peggy Bundy — G. Married… With Children
6. Sophia Petrillo — K. The Golden Girls
7. Claire Dunphy — J. Modern Family
8. Florida Evans — E. Good Times
9. Maggie Seaver — F. Growing Pains
10. Thelma Harper — A. Mama’s Family
11. Harriette Winslow — I. Family Matters
12. Jane Jetson — C. The Jetsons

How did you do? Are you a Mother’s Day puzzle master, or did you sitcom this one out?

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Happy Mother’s Day!

Today is Mother’s Day, and as always, I’d like to celebrate with a puzzle! So, in honor of the day and mother’s everywhere, I’ve conjured up a Penny/Dell Puzzles-style Unscramblers puzzle for you!

Rearrange the pairs of letters in the left-hand column to form the names of 12 TV sitcom moms. Then match them with their TV shows in the right-hand column!

Enjoy! And Happy Mother’s Day to all the marvelous, wonderful, inspiring, hard-working moms out there!

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It’s Follow-Up Friday: Birthday Puzzle edition!

Welcome to Follow-Up Friday!

By this time, you know the drill. Follow-Up Friday is a chance for us to revisit the subjects of previous posts and bring the PuzzleNation audience up to speed on all things puzzly.

And today, I’d like to return to the subject of birthday brain teasers!

Working on the Cheryl’s Birthday brain teaser a few days ago reminded me of another birthday-fueled puzzle that’s been around forever.

How many people do you need to enter a room before the probability of any 2 or more people sharing a birthday (day and month only, not year) is greater than 50%?

Assume for the sake of the puzzle that birthdays in the population at large are equally spread over a 365 day year.

Now, given that there are 365 days in the year, you’d assume the number of people necessary to get that probability of a shared birthday above 50% would be more than half of 365, or 183 people.

But it turns out that, statistically speaking, you don’t need anywhere near that many people.

Let’s break it down. Person A has a birthday. Person B has a birthday. There’s only one possible pairing, A-B. Person C has a birthday, but creates three possible birthday pairings: A-B, A-C, and B-C.

Person D could have a different birthday, but the introduction of Person D begins escalating the number of POSSIBLE shared birthdays. With these four people, we have SIX possible pairings: A-B, A-C, A-D, B-C, B-D, and C-D.

Our fifth person, Person E, allows for TEN possible pairings: A-B, A-C, A-D, A-E, B-C, B-D, B-E, C-D, C-E, and D-E. The probability of a shared birthday is increasing much faster with each new person.

As it turns out, it only takes 23 people to give us a 51% probability of a shared birthday.

And that would certainly save on catering.

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